Monday, February 3, 2014

Aerocarnival

4)It took MegaTech, Inc. 100,000 labor-hours to evoke the get-go of several oil bore rigs for frigid exploration. Your company, Natural Resources, Inc. has agreed to purchase the fifth oil oil production rig from their manufacturing yard. Assume that MegaTech experiences a learning send of 80%. At a labor rate of $35 per hour, what should you, as the purchasing agent expect to pay for the fifth substantial? Remember, the simplified formula for calculating learning rate placard is given as: TN = T1C Where, TN = Time needed to produce the n-th unit of measurement T1= Time needed to produce the first unit C= acquirement curved shape coefficient Answer The circumvent lists the fourth unit learning curve coefficient as .596, presumptuous a learning rate of 80%. Using the formula, to produce the fifth unit takes: T5 = (100,000) (.596) = 59,600 hours To find the personify, calculate the hours by the periodic rate: = (59,600) ($35 per hour) = $2,086 ,000 6)Suppose that you ar the assigning costs to a major go out to be undertaken by your firm, DynoSoft Applications, this year. One item code process involves some(prenominal) labor hours, but highly purposeless work. You anticipate a total of 200,000 labor hours to complete the first grummet of the coding and a learning curve rate of 70%. You be attempting to estimate the cost of the twentieth cringle of this coding sequence. establish on the above information and at a $60 per hour labor rate, what would you expect to compute as the cost of the twentieth grommet? The fortieth iteration? Answer T20=T1C =(200,000) (.214) =42,800 hours T40=T1C =(200,000) (.150) =30,000 hours The costs for the twentieth and 40th iterations atomic cast 18 found as: 20th iteration: (42,800 hours) ($60 per hour) =$2,568,000 40th iteration: (30,000 hours) ($60 per hour) =$1,800,000 7)Assume you are a project cost engineer calculating th e cost of a exigent activity for your proje! ct. There are a total of 20...If you exigency to get a full essay, straddle it on our website: BestEssayCheap.com

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